Final answer:
To determine if there is a significant difference among the average hourly wages in the three areas, an analysis of variance (ANOVA) test is performed. The calculated F-value is less than the critical value, indicating that there is no significant difference among the average hourly wages in the three areas.
Step-by-step explanation:
To determine if there is a significant difference among the average hourly wages in the three areas, we need to perform an analysis of variance (ANOVA) test. The first step is to calculate the mean and variance for each area:
Area 1: Mean = (21 + 17 + 19 + 11 + 15) / 5 = 17.6, Variance = [(21-17.6)^2 + (17-17.6)^2 + (19-17.6)^2 + (11-17.6)^2 + (15-17.6)^2] / 4 = 5.7
Area 2: Mean = (10 + 10 + 17 + 22 + 18) / 5 = 15.4, Variance = [(10-15.4)^2 + (10-15.4)^2 + (17-15.4)^2 + (22-15.4)^2 + (18-15.4)^2] / 4 = 21
Area 3: Mean = (15 + 16 + 22 + 24 + 22) / 5 = 19.8, Variance = [(15-19.8)^2 + (16-19.8)^2 + (22-19.8)^2 + (24-19.8)^2 + (22-19.8)^2] / 4 = 8.6
Next, we can calculate the overall mean and variance:
Overall Mean = (17.6 + 15.4 + 19.8) / 3 = 17.6, Overall Variance = [(17.6-17.6)^2 + (15.4-17.6)^2 + (19.8-17.6)^2] / 2 = 4.7
Now we can calculate the sum of squares:
Sum of Squares Between Groups = (5 * (17.6-17.6)^2 + 5 * (15.4-17.6)^2 + 5 * (19.8-17.6)^2) / 2 = 0.84
Sum of Squares Within Groups = [(21-17.6)^2 + (17-17.6)^2 + (19-17.6)^2 + (11-17.6)^2 + (15-17.6)^2 + (10-15.4)^2 + (10-15.4)^2 + (17-15.4)^2 + (22-15.4)^2 + (18-15.4)^2 + (15-19.8)^2 + (16-19.8)^2 + (22-19.8)^2 + (24-19.8)^2 + (22-19.8)^2) / 4 = 81.4
Finally, we can calculate the F-value:
F = (0.84 / 2) / (81.4 / 12) = 0.07
Since the calculated F-value is less than the critical value, we fail to reject the null hypothesis. Therefore, there is no significant difference among the average hourly wages in the three areas.