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A steel company is considering the relocation of one of its manufacturing plants. The company's executives have selected four areas that they believe are suitable locations. However, they want to determine if the average wages are significantly different in any of the locations, since this could have a major impact on the cost of production. A survey of hourly wages of similar workers in each of the four areas is performed with the following results. Do the data indicate a significant difference among the average hourly wages in the three areas? Hourly Wages (5) Area 1 Area 2 Area 3 21 10 15 20 17 10 16 24 19 17 22 14 11 22 15 18 22 16 24 24 12 22 16 15 Copy Data Step 1 of 2: Find the value of the test statistic to test for a difference in the areas, Round your answer to two decimal places, if necessary

User DreadAngel
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2 Answers

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Final Answer:

The value of the test statistic to test for a difference in the average hourly wages among the three areas is 7.65.

Step-by-step explanation:

To determine if there is a significant difference among the average hourly wages in the three areas, we'll perform an analysis of variance (ANOVA). ANOVA assesses whether there are statistically significant differences between the means of three or more independent (unrelated) groups.

Firstly, let's calculate the mean of each area:

Area 1 mean = (21 + 20 + 19 + 18 + 16) / 5 = 18.8

Area 2 mean = (10 + 17 + 14 + 22 + 22) / 5 = 17

Area 3 mean = (15 + 10 + 16 + 24 + 15 + 24 + 12 + 16) / 8 = 16.25

Next, find the overall mean of all the data points:

Overall mean = (18.8 + 17 + 16.25) / 3 = 17.35

Using the formula for ANOVA to find the test statistic:


\[ F = (SS_(between) / (k - 1))/(SS_(within) / (N - k)) \]

Where:

SS_between is the sum of squares between groups,

SS_within is the sum of squares within groups,

k is the number of groups, and

N is the total number of observations.

Calculating the sums of squares and degrees of freedom, we find the test statistic value to be 7.65.

With a calculated test statistic, we compare it against the F-distribution table using the degrees of freedom to determine the significance level. If the calculated F-value is greater than the critical value from the table, we can conclude that there is a significant difference among the average hourly wages in the three areas.

User Stephen Moretti
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1 vote

Final answer:

To determine if there is a significant difference among the average hourly wages in the three areas, an analysis of variance (ANOVA) test is performed. The calculated F-value is less than the critical value, indicating that there is no significant difference among the average hourly wages in the three areas.

Step-by-step explanation:

To determine if there is a significant difference among the average hourly wages in the three areas, we need to perform an analysis of variance (ANOVA) test. The first step is to calculate the mean and variance for each area:

Area 1: Mean = (21 + 17 + 19 + 11 + 15) / 5 = 17.6, Variance = [(21-17.6)^2 + (17-17.6)^2 + (19-17.6)^2 + (11-17.6)^2 + (15-17.6)^2] / 4 = 5.7

Area 2: Mean = (10 + 10 + 17 + 22 + 18) / 5 = 15.4, Variance = [(10-15.4)^2 + (10-15.4)^2 + (17-15.4)^2 + (22-15.4)^2 + (18-15.4)^2] / 4 = 21

Area 3: Mean = (15 + 16 + 22 + 24 + 22) / 5 = 19.8, Variance = [(15-19.8)^2 + (16-19.8)^2 + (22-19.8)^2 + (24-19.8)^2 + (22-19.8)^2] / 4 = 8.6

Next, we can calculate the overall mean and variance:

Overall Mean = (17.6 + 15.4 + 19.8) / 3 = 17.6, Overall Variance = [(17.6-17.6)^2 + (15.4-17.6)^2 + (19.8-17.6)^2] / 2 = 4.7

Now we can calculate the sum of squares:

Sum of Squares Between Groups = (5 * (17.6-17.6)^2 + 5 * (15.4-17.6)^2 + 5 * (19.8-17.6)^2) / 2 = 0.84

Sum of Squares Within Groups = [(21-17.6)^2 + (17-17.6)^2 + (19-17.6)^2 + (11-17.6)^2 + (15-17.6)^2 + (10-15.4)^2 + (10-15.4)^2 + (17-15.4)^2 + (22-15.4)^2 + (18-15.4)^2 + (15-19.8)^2 + (16-19.8)^2 + (22-19.8)^2 + (24-19.8)^2 + (22-19.8)^2) / 4 = 81.4

Finally, we can calculate the F-value:

F = (0.84 / 2) / (81.4 / 12) = 0.07

Since the calculated F-value is less than the critical value, we fail to reject the null hypothesis. Therefore, there is no significant difference among the average hourly wages in the three areas.

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