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What is an equation of the line that passes through the points (-9,0) and (6,-5)

User Dajnz
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1 Answer

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Answer:

y=-1/3x-3

Explanation:

First, we should find the slope

The equation for slope is
m=(y_2-y_1)/(x_2-x_1) where m is the slope and the x's and y's are points on the line.

Plug in points


m=\frac {0-(-5)}{-9-6}\\m=(5)/(-15) \\m=-(1)/(3)

Meaning the slope is -1/3

The slope intercept form is y=mx+b where m is the slope and b is the y intercept (so far the equation is y=-1/3x+b)

We can also find b by plugging in a point

For example, let's use point (-9,0)


y=-(1)/(3) x+b\\0=-(1)/(3) (-9)+b\\0=3+b\\b=-3

Finally, to check, we can use point (6,-5)


-5=-(1)/(3) (6)-3\\-5=-2-3\\-5=-5\\True

User Andrea Zonca
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