135k views
4 votes
What is an equation of the line that passes through the points (-9,0) and (6,-5)

User Dajnz
by
7.5k points

1 Answer

0 votes

Answer:

y=-1/3x-3

Explanation:

First, we should find the slope

The equation for slope is
m=(y_2-y_1)/(x_2-x_1) where m is the slope and the x's and y's are points on the line.

Plug in points


m=\frac {0-(-5)}{-9-6}\\m=(5)/(-15) \\m=-(1)/(3)

Meaning the slope is -1/3

The slope intercept form is y=mx+b where m is the slope and b is the y intercept (so far the equation is y=-1/3x+b)

We can also find b by plugging in a point

For example, let's use point (-9,0)


y=-(1)/(3) x+b\\0=-(1)/(3) (-9)+b\\0=3+b\\b=-3

Finally, to check, we can use point (6,-5)


-5=-(1)/(3) (6)-3\\-5=-2-3\\-5=-5\\True

User Andrea Zonca
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories