Question

Curriculum-Bas Algebraic Equations Part 1 Use PEMDAS to prove that both sides are equal. Sho 6*3+3*-3=3^{2}+1^{2}-1

Answer 1

6 x 3 + 3 x (-3)= 3^2 +1^2 - 1

First we will solve the left side.

Using the M (multiplication) in PEMDAS we will simply the left side like this :

18+(-9)

simplify by using the A (addition) in PEMDAS

9= 3^2 + 1 ^2 -1

Now the right side

We will use the E (exponents) to solve 3^2 and 1^2

9= 9+1 -1

Next is the A (addition)

9= 10-1

Finally is the S (subtraction)

9=9