Question

A bag contains 3 brown and 4 green M&Ms. One M&M is drawn at random and the color is observed. The M&M is then replaced in the bag and a second M&M is drawn at random. What is the probability that both M&Ms were brown? 0.750 0.245 0.184 0.327

Answer 1

Answer:To find the probability that both M&Ms drawn are brown, we need to consider the probability of drawing a brown M&M on the first draw and then the probability of drawing a brown M&M on the second draw.

The probability of drawing a brown M&M on the first draw is 3/7, because there are 3 brown M&Ms out of a total of 7 M&Ms in the bag.

Since the first M&M is replaced back into the bag before the second draw, the probabilities for each draw are independent. This means that the probability of drawing a brown M&M on the second draw is also 3/7.

To find the probability of both events happening, we multiply the probabilities together:

(3/7) * (3/7) = 9/49

So, the probability that both M&Ms drawn are brown is 9/49.

In decimal form, this is approximately 0.184.

Therefore, the correct answer is 0.184.