Question

What expression should each side of (4x-1)/((x+2)(4x^(2)+1))=(A)/(x+2)+(Bx+C)/(4x^(2)+1) be multiplied by so that there are no fractions in the equation?

Answer 1

To eliminate the fractions in the equation, multiply both sides by the common denominator of the fractions.

Step-by-step explanation:

To eliminate the fractions in the equation, we need to find a common denominator for both fractions on the right side. The common denominator is (x+2)(4x^2+1).

So we can multiply the first fraction on the left side by (x+2)(4x^2+1) and the second fraction on the right side by 1. This will give us:

(4x-1)(x+2)(4x^2+1) = A(x+2)(4x^2+1) + (Bx+C)

Learn more about Eliminating fractions