Question

What is the distance in the standard (x,y) coordinate plane between the points (0,2) and (-5,0) ?

Answer 1

d ≈ 5.4

Explanation:

calculate the distance d using the distance formula

d =
`\sqrt{(x_(2)-x_(1))^2+(y_(2)-y_(1))^2 }`

let (x₁, y₁ ) = (0, 2 ) and (x₂, y₂ ) = (- 5, 0 )

substitute these values into the formula for d

d =
`√((-5-0)^2+(0-2)^2)`

=
`√((-5)^2+(-2)^2)`

=
`√(25+4)`

=
`√(29)`

≈ 5.4 ( to 1 decimal place )