Question

His initial speed is 5.00m/s. The rocket accelerates him uniformly from 5.00 m/s to 25.0 m/s in 5.00s. Determine the distance Wile E travels during the first 5 seconds after igniting the rocket.(75.0m)

Answer 1

S = V0 t + 1/2 a t^2 standard equation for distance traveled where t = 5 sec

a = (25 - 5) m/s / 5 s = 4 m/s^2

S = 5 * 5 + 1/2 * 4 * 5^2 = (25 + 50) m = 75 m