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Watch help video Given sin\theta =(6)/(7) and angle \theta is in Quadrant II, what is the exact value of cos\theta in simplest form? Simplify all radicals if needed.
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Watch help video Given sin\theta =(6)/(7) and angle \theta is in Quadrant II, what is the exact value of cos\theta in simplest form? Simplify all radicals if needed.

User Pirmax
by
7.7k points

1 Answer

7 votes

Answer:


-√(13) /7\\\\\\

Explanation:


\sqrt{1-((6)/(7))^(2) } =√(13) /7\\\\\\

negative because it's in quadrant II

User Rudrik
by
8.4k points
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