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Determine the asymptotes for the function. g(x)=(x^(2)-4x-5)/(x^(3)-6x^(2)+9x)

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The function g(x) = (x^2 - 4x - 5)/(x^3 - 6x^2 + 9x) is a rational function. To determine the asymptotes for this function, we need to consider both horizontal and vertical asymptotes.

1. Vertical Asymptotes:

Vertical asymptotes occur when the denominator of a rational function equals zero. In this case, we need to find the values of x that make the denominator, x^3 - 6x^2 + 9x, equal to zero.

To find these values, we can factor the denominator:

x^3 - 6x^2 + 9x = x(x^2 - 6x + 9) = x(x - 3)^2.

Setting each factor equal to zero, we find:

x = 0 (from x = 0)

x - 3 = 0 (from x - 3 = 0)

So, the vertical asymptote(s) for the function g(x) occur at x = 0 and x = 3.

2. Horizontal Asymptotes:

To find the horizontal asymptotes, we need to compare the degrees of the numerator and denominator.

The degree of the numerator is 2 (highest power of x is x^2), and the degree of the denominator is 3 (highest power of x is x^3).

Since the degree of the numerator is less than the degree of the denominator, there is a horizontal asymptote at y = 0, which is the x-axis.

Therefore, the function g(x) has vertical asymptotes at x = 0 and x = 3, and a horizontal asymptote at y = 0 (the x-axis).

Remember, asymptotes are imaginary lines that the graph of a function approaches but never touches. They can help us understand the behavior of a function as x gets very large or very small.

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