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Find the equation of a line parallel to 3x+2y=14 that passes through the point (8,8)

User Yevg
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1 Answer

5 votes

Answer:

y = -3/2 x + 20

Explanation:

First of all we have to put the equation in this form

y = mx + h

Move 3x to right side of equal by changing its sign

2y = -3x + 14

Divide each number by 2

2/2 y = -3/2 x + 14/2

y = -3/2 x + 7


the slope of the line is -3/2

Two parallel lines have the same slope, so the slope of the line we are searching for is -3/2


Now we can use this formula, that suites for lines that pass for one point with a given slope


y - y of point = slope (x - x of point)


Substitute with the given data

y-8 = -3/2(x-8)

y- 8 = -3/2 x + 24/2

y - 8 = -3/2 x + 12

y = - 3/2 x + 12 + 8

y = -3/2 x + 20

User Awanish Raj
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