Question

DESCRIPTIVE STATISTICS Variable score N 50 Mean 1045.7 Median 10247 TY Mean 10419 SDev 21.9 SE Mean 314 Variable cate Minimum 5229 Maximum 15771 Q1 872.7 03 1219.5 Some descriptive statistics for a set of test scores are shown above. For this test, a certain student has a standardized score of z=-1.2 What score did this student receive on the test? A. 266.28 B 779.42 C. 1008.02 D. 1083 38 E 1311 98

Answer 1

Using the z-score formula, the student's actual test score is calculated to be 1019.42, which is 1.2 standard deviations below the mean.

Step-by-step explanation:

To determine the actual test score from a standard z-score, one can use the formula derived from the definition of the z-score: z = (X - μ) / σ. Here, X is the test score, μ (mu) is the mean of the test scores, and σ (sigma) is the standard deviation. To find X, we rearrange the formula to X = μ + zσ.

Given that the z-score is -1.2, the mean is 1045.7, and the standard deviation is 21.9, we can calculate the student's score (X) as follows:

X = μ + zσ
X = 1045.7 + (-1.2)(21.9)
X = 1045.7 - 26.28
X = 1019.42

Therefore, the student's test score is 1019.42. Due to the typos in the initial multiple-choice options given, Option B is close but not entirely accurate as it would be 1019.42 instead.