Answer:
Δ = 121
Explanation:
given a quadratic equation in standard form
ax² + bx + c = 0 ( a ≠ 0 )
then the discriminant Δ is calculated as
Δ = b² - 4ac
given
4x² - 13x + 3 = 0 ← in standard form
with a = 4 , b = - 13 , c = 3 , then the discriminant is
b² - 4ac
= (- 13)² - ( 4 × 4 × 3 )
= 169 - 48
= 121