Question

Find the 30th term of the sequence 2 6 10 14 answer

Answer 1

a₃₀ = 118

Explanation:

there is a common difference between consecutive terms in the sequence, that is

6 - 2 = 10 - 6 = 14 - 10 = 4

this indicates the sequence is arithmetic with nth term given by

`a_(n)` = a₁ + d(n - 1)

where a₁ is the first term and d the common difference

here a₁ = 2 and d = 4 , substitute into the nth term formula

a₃₀ = 2 + (4 × 29) = 2 + 116 = 118