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A cylindrical bead is made by removing a cylinder of base radius 3 mm from a cylinder of base radius 7 mm. If both cylinders have a height of 8 mm, what is the volume of the bead? (Take π=3.14) a.327.1 mm³ b.551.4 mm³ c.882 mm³ d.1004.8 mm³ ​

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Final answer:

To find the volume of the bead, we subtract the volume of the smaller cylindrical hole from the volume of the larger cylinder. The volumes of the cylinders are calculated using the formula for cylinder volume V = πr²h. The closest answer is 1004.8 mm³.

Step-by-step explanation:

The concept involved in this question belongs to the field of Mathematics, specifically, Geometry. To find the volume of the bead, we need to subtract the volume of the smaller cylinder that was removed from the larger cylinder.

The volume of a cylinder is given by the formula V = πr²h where r is the radius and h is the height. The volume of the larger cylinder (base radius 7 mm, height 8 mm) is V1 = π × 7² × 8 = 1232 mm³.

The volume of the smaller cylinder (base radius 3 mm, height 8 mm) is V2 = π × 3² × 8 = 226.08 mm³.

By subtracting V2 from V1, we can find the volume of the bead. So, V = V1 - V2 = 1232 - 226.08 = 1005.92 mm³. Therefore, the closest answer is d. 1004.8 mm³.

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