Final answer:
To find the length and width of a rectangle with a perimeter of 20yd and area of 16yd^2, we can use mathematical formulas. The possible lengths and widths which satisfy these conditions are (1,9) and (2,8), but the only pair that multiplies to give the area of 16yd^2 is (2,8). Therefore, the length is 8yd and the width is 2yd.
Step-by-step explanation:
In mathematics, to calculate the length and width of a rectangle given the perimeter and area, we can use the formulas P=2L+2W (Perimeter equals twice the length plus twice the width), and A=L*W (Area equals length times width). In this specific case, the perimeter is 20yd and the area is 16yd2.
Let's set the length as 'L' and width as 'W'. We can find two possible pairs of 'L' and 'W' which satisfy these conditions: (1,9) and (2,8). However, the pair (2,8) is the only one that multiplies to give an area of 16yd2, so the length is 8 yards and the width is 2 yards.
Learn more about Area and Perimeter