Question

What is the equation of the line that contains the following points?
(1,3) and (-3,-5)

Answer 1

y = 2x + 1

Explanation:

First find the slope

rise/run

m = -5-3 / -3 -1

m = -8/-4

m = 2

Now that we have the slope (m), we can find the y-intercept (b) by substituting the coordinates of one of the points into the equation y = mx + b.

Using the point (-3,-5), we have:

-5 = -3(2) + b

-5 = -6 + b

b = 1

∴

the equation of the line that contains the points (1,3) and (-3,-5) is y = 2x + 1.