Answer:
A.) f(-3) + f(2) = 32
B.) f(-3) - f(2) = 0
Explanation:
We need to find the value of f(-3) and f(2) in the expression x² + x + 10
When f(x) = -3, (-3)² - 3 + 10
9 - 3 + 10
6 + 10
16
f(-3) = 16
now let's find the f(2)
When f(x) = 2, 2² + 2 + 10
4 + 2 + 10
16
f(2) = 16
A.) f(-3) + f(2) = 16 + 16
f(-3) + f(2) = 32
B.) f(-3) - f(2) = 16 - 16
f(-3) + f(2) = 0