Question

Pb(s)+NO 3 ^ - (aq) longrightarrow Pb^ 2+ (aq)+NO(g) Express your answer as a chemical equation. Identify all of the phases in your answer

Answer 1

The student has asked for a balanced equation and phase identification. The corrected equation is Pb(s) + 2 NO₂⁻. → Pb²+(aq) + 2 NO(g) with lead in solid form, nitrate in aqueous solution, lead(II) ion in aqueous solution, and nitrogen monoxide in gaseous form.

Step-by-step explanation:

The student is asking for a balanced chemical equation and the identification of the phases for each substance in the reaction.

The correct balanced equation for the reaction given should be:

Pb(s) + 2 NO₃⁻(aq) → Pb²⁺(aq) + 2 NO(g)

Now, let's identify the phases:

• Pb(s) is lead in its solid form.
• NO₃⁻(aq) is the nitrate ion in an aqueous solution.
• Pb²⁺(aq) is the lead(II) ion in an aqueous solution.
• NO(g) is nitrogen monoxide in its gaseous form.

Note: The provided equation appears to have a mismatch with the reaction in question. There seems to be a confusion between Pb and Pb(NO₃)₂ and between nitrite (NO₂⁻.) and nitrate (NO).

Answer 2

The equation provided by the student is unbalanced and needs correction. A correct example of a balanced chemical equation is Pb(NO3)2 (aq) + 2 NaCl (aq) → 2 NaNO3 (aq) + PbCl2 (s), which respects the law of conservation of mass by having an equal number of each type of atom on both sides of the equation.

Step-by-step explanation:

The given chemical equation is: Pb(s) + NO3- (aq) long right arrow Pb2+ (aq) + NO(g)

This equation is not balanced as it stands. However, to balance it, we might consider a different reaction example that is balanced: Pb(NO3)2 (aq) + 2 NaCl (aq) → 2 NaNO3 (aq) + PbCl2 (s)

After counting the number of each atom on both sides of the equation, we find that:

1. There is 1 Pb atom on both the reactant and product sides.
2. There are 2 Na atoms on both the reactant and product sides.
3. There are 2 Cl atoms on both the reactant and product sides.
4. There are 2 NO3 ions on both the reactant and product sides.

This equation demonstrates the principles of balancing a chemical equation and ensures that the law of conservation of mass is observed. In a balanced equation, the number of each type of atom is equal on both sides of the equation, meaning no atoms are lost or gained in the chemical reaction.