Final answer:
The equation of the line parallel to y = 4x - 5 passing through (-2, 3) is y = 4x + b, and to find the value of b, we substitute the coordinates (-2, 3) into the equation and solve for b. The equation of the line perpendicular to y = 3x - 5 passing through (-2, 3) is y - 3 = -1/3(x - (-2)).
Step-by-step explanation:
To find the equation of a line parallel or perpendicular to a given line, we need to know the slope of the given line. For the line y = 4x - 5, the slope is 4, so any line parallel to it will have the same slope. Therefore, the equation of the line parallel to y = 4x - 5 passing through (-2, 3) is y = 4x + b. To find the value of b, we substitute the coordinates (-2, 3) into the equation and solve for b. For the line perpendicular to y = 3x - 5, the slope is the negative reciprocal of 3, which is -1/3. Using the point-slope form, the equation of the line perpendicular to y = 3x - 5 passing through (-2, 3) is y - 3 = -1/3(x - (-2)).
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