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A sample of an unknown gas is in a container that has a piston attached to it with a volume of 692.5 mL and at a pressure of 2.9 alm. What is the volume of the container. in L. If the pressure is decreased to 828.6 Torre

User Frankish
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Final answer:

Using Boyle's Law, which states that pressure and volume of a gas are inversely related when temperature is held constant, we find the volume of the unknown gas in the new scenario to be 1.8507 L.

Step-by-step explanation:

The given question is related to the behavior of gases and their properties which are governed by the gas laws. In this case, it is about Boyle's Law which states that the pressure and volume of a gas have an inverse relationship when temperature is held constant. Therefore, if we have an unknown gas in a container with a piston attached to it and we know the initial volume (V1) and pressure (P1), we can use this law to find the final volume (V2) when the pressure (P2) is changed.

Given, V1 = 692.5 mL, P1 = 2.9 atm and P2 = 828.6 torr. Firstly, let's ensure the pressure is in the same units, so convert the given P2 from Torr to atm, which gives approximately P2 = 1.09 atm. Now applying Boyle's law: V1 * P1 = V2 * P2. Solving for V2, we get V2 = (V1 * P1) / P2 = (692.5 mL * 2.9) / 1.09 = 1850.7 mL. Converting mL to L, we get V2 = 1.8507 L.

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User Philipp Jahoda
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