8.4k views
1 vote
Divide (5x+20)/(x^(2)-5x-14)-:(x^(2)+7x+12)/(x+2) (Remember to flip the second fraction! )

User Pisker
by
7.9k points

1 Answer

0 votes

Final answer:

The expression (5x+20)/(x^2 - 5x - 14) ÷ (x^2 + 7x + 12)/(x + 2) simplifies to 5/[(x-2)(x+3)] by flipping the second fraction and then doing multiplication and factoring.

Step-by-step explanation:

The process of dividing two fractions involves flipping (also known as finding the reciprocal of) the second fraction and then multiplying. The given expression is (5x+20)/(x^2 - 5x - 14) ÷ (x^2 + 7x + 12)/(x + 2). To do this, we can follow these steps:

  1. Flip the second fraction to get (x + 2)/(x^2 + 7x + 12).
  2. Multiply the two fractions to get [(5x+20)/(x^2 - 5x - 14)]*(x + 2)/(x^2 + 7x + 12).
  3. Factor everything. The multiplication turns into [(5(x+4))/((x-2)(x+7))]*[(x + 2)/((x+4)(x+3))].
  4. Cancel out the common factors to finish the simplification. You are left with 5/(x-2)*(1/x+3), which can be simplified further to 5/[(x-2)(x+3)].

Learn more about Fraction Division

User Jackson Davis
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories