Question

PLEASE HELP URGENT A cart travels along a straight section of road. A velocity vs time graph illustrating its motion is graphed above. What is the distance of the cart from t = 0s to t = 15s?

Answer 1

47.5 meters

Explanation:

area of a velocity time graph is equal to the displacement, but since we want the distance, all areas will be considered positive

triangle from a to c: 1/2*6*5=15

trapezoid from c to g: (4+9)5/2=32.5

15+32.5=47.5m