Question

A super ball dropped from rest falls 2 meters vertically downward and rebounds 2 meters upward in a total time of 1.6 seconds. Just as it arrives at its initial starting point, what are the magnitude of the average velocity and the average speed, respectively? Ozero and 2.5 m/s O 2.5 m/s and 2.5 m/s 1.3 m/s and 1.3 m/s 2.5 m/s and zero O 0 m/s and 1.3 m/s

Answer 1

The magnitude of the average velocity is zero meters per second and the magnitude of the average speed is 2.5 meters per second.

Step-by-step explanation:

When a super ball is dropped from rest and it falls 2 meters vertically downward and rebounds 2 meters upward, it completes one full cycle. We are given that the total time for this cycle is 1.6 seconds. To find the average velocity, we need to divide the total displacement (0 meters) by the total time (1.6 seconds). Since the displacement is zero, the average velocity is also zero meters per second.

On the other hand, to find the average speed, we need to divide the total distance traveled (2 meters + 2 meters = 4 meters) by the total time (1.6 seconds). Therefore, the average speed is 4 meters divided by 1.6 seconds, which is 2.5 meters per second.