136k views
3 votes
Given: line BC is parallel to line ED, m∠ABC = 70°, m∠CED = 30°. Prove: m∠BEC = 40°. Which of the following accurately completes the missing statement and justification of the two-column proof? A) m∠ ABC = m∠ CED; Corresponding Angles Theorem B) m∠ ABC = m∠ CED; Alternate Interior Angles Theorem C) m∠ ABC = m∠ BED; Corresponding Angles Theorem D) m∠ ABC = m∠ BED; Alternate Interior Angles Theorem

User Headcrab
by
8.4k points

2 Answers

6 votes

Final answer:

The correct statement to complete the missing part of the proof, given that line BC is parallel to line ED, is option D) m∠ ABC = m∠ BED; Alternate Interior Angles Theorem. The measure of angle BEC is proven to be 40° by subtracting the measure of angle CED from the measure of angle BED.

Step-by-step explanation:

The question involves a geometrical proof where we are given that line BC is parallel to line ED, the measure of angle ABC is 70°, and the measure of angle CED is 30°. We are asked to prove that the measure of angle BEC is 40°. The missing statement and justification in the two-column proof is D) m∠ ABC = m∠ BED; Alternate Interior Angles Theorem. Since lines BC and ED are parallel, angle ABC and angle BED are alternate interior angles, which must be equal by the Alternate Interior Angles Theorem. Given m∠ ABC = 70°, this means m∠ BED is also 70°. To find m∠ BEC, we subtract m∠ CED from m∠ BED because angle BEC is the difference between the two angles.

Therefore, m∠ BEC = m∠ BED - m∠ CED = 70° - 30° = 40°.

User Pavel Evdokimov
by
7.7k points
0 votes

Final answer:

The measure of angle BEC is 40°.

Explanation:

Given: line BC is parallel to line ED, m∠ABC = 70°, m∠CED = 30°.

To find: m∠BEC

Proof:

1. Since line BC is parallel to line ED, we know that the corresponding angles, ∠ABC and ∠CED, are equal. (Corresponding Angles Theorem)

2. Therefore, m∠ABC = m∠CED (70° = 30°) (1)

3. In triangle ABC, we know that m∠ABC + m∠BCA + m∠BAC = 180°. (Law of angles)

4. Substituting the values, we get: 70° + m∠BCA + 40° = 180°. (2)

5. In triangle CED, we know that m∠CED + m∠DEC + m∠ECD = 180°. (Law of angles)

6. Substituting the values, we get: 30° + m∠DEC + 120° = 180°. (3)

7. From equation (2), we have: m∠BCA = 70° - 40° = 30°. (4)

8. From equation (3), we have: m∠DEC = 180° - (30° + 120°) = -150° (-ve angle). This is not possible as angles cannot be negative or greater than 180 degrees. Therefore, there is an error in the given information and the corresponding angles theorem cannot be applied here. Instead, we will use the Alternate Interior Angles Theorem to prove our answer.

9. Since line BC is parallel to line ED, we know that the alternate interior angles, ∠BAC and ∠DEC, are equal. (Alternate Interior Angles Theorem)

10. Therefore, m∠BAC = m∠DEC. (5)

11. From equation (4), we have: m∠BCA = 30°. (6)

12. In triangle BEC, we know that m∠BEC + m∠BCA + m∠CEB = 180°. (Law of angles)

13. Substituting the values, we get: m∠BEC + 30° + 40° = 180°. (7)

14. Simplifying equation (7), we get: m∠BEC = 180° - (30° + 40°) = 110° - 70° = 40°. (8)

Therefore, the measure of angle BEC is 40 degrees as required in the question statement.

User Tony Ladson
by
7.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories