Answer:
the sum of the supplementary angles = 180°
ABC =(3m-15)° and m ABD=(5m+59)°
(3m-15)°+(5m+59)°=180
3m-15+5m+59=180
8m+44 = 180
8m = 180-44
m =136/8=17°
m= 17°
∠ABC = 3*17-15=36°
∠ABD = 5*17+59=144°
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