Answer:
1 , 3 , 7 , 13
Explanation:
to find the first 4 terms , substitute , n = 1 , 2 , 3 , 4 into t(n)
t(n) = n² - n + 1
then
t(1) = 1² - 1 + 1 = 1 - 1 + 1 = 0 + 1 = 1
t(2) = 2² - 2 + 1 = 4 - 2 + 1 = 2 + 1 = 3
t(3) = 3² - 3 + 1 = 9 - 3 + 1 = 6 + 1 = 7
t(4) = 4² - 4 + 1 = 16 - 4 + 1 = 12 + 1 = 13
the first 4 terms are 1 , 3 , 7 , 13