Question

Which equation is the inverse of the y=7×^2-10?​

Answer 1

I think the choose (2)

`y = - + \sqrt{ (x + 10)/(7) }`

Answer 2

option B

Explanation:

Given :

`y = 7x^2 - 10`

Replace x and y :

`x = 7y^2 - 10 \\`

Now solve for y :

`x = 7y^2 - 10 \\\\x + 10 = 7y^2 - 1 0+ 10`
`[ \ adding \ 10 \ on \ both \ sides \ ]`

`x + 10 = 7y^2\\\\(x + 10 )/(7 ) = (7y^2)/(7)`
`[ \ dividing\ by \ 7 \ on \ both \ sides \ ]`

`(x+ 10)/(7) = y^2\\\\\pm \ \sqrt{(x+ 10)/(7)} = y`