Final answer:
The volume of NO gas produced when 708 L of NO2 gas reacts with water is 236 L.
Step-by-step explanation:
In this question, we will use the principle of stoichiometry to determine the volume of NO gas produced when 708 L of NO2 gas reacts with water. The balanced chemical equation for this reaction is:
3 NO2 + H2O → 2 HNO3 + NO
From the balanced equation, we can see that for every 3 L of NO2, 1 L of NO is produced.
Therefore, if we have 708 L of NO2, we can divide it by 3 to find the volume of NO gas produced, which is
Option 2: 236 L
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