Question

For water softening, you need a sodium carbonate solution (c = 5.0 g/L). How many grams of sodium carbonate do you need to weigh out for 1.2 dm3 of this solution?

Answer 1

Answer:To find out how many grams of sodium carbonate are needed for 1.2 dm³ of a 5.0 g/L solution, we can use the following formula:

Mass

=

Concentration

×

Volume

Mass=Concentration×Volume

Given:

Concentration (

c) = 5.0 g/L

Volume (

V) = 1.2 dm³

Make sure the units are compatible. Since the concentration is given in g/L and the volume is in dm³, they are already compatible.

Plugging in the values:

Mass

=

5.0

 

g/L

×

1.2

 

dm

3

Mass=5.0g/L×1.2dm

3

Mass

=

6.0

 

grams

Mass=6.0grams

So, you would need to weigh out 6.0 grams of sodium carbonate for 1.2 dm³ of this solution.

Step-by-step explanation: