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Sin alpha = 3/5 find cos alpha and tan alpha

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Explanation:

Use the following identities:

sin²x + cos²x = 1

tan x = sin x / cos x

sin²α + cos²α = 1

(3/5)² + cos²α = 1

9/25 + cos²α = 1

cos²α = 16/25

cos α = ±4/5

tan α = sin α / cos α

tan α = (3/5) / (±4/5)

tan α = ±3/4

Therefore, cos α = ±4/5 and tan α = ±3/4, depending on the quadrant that α is in.

User Kevmar
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