Question

Write the quadratic equation (x-2) (x+3)=0 in standard form.

Answer 1

`x^(2) + x - 6 = 0`

Explanation:

You just have to multiply out the terms, have you learned how to do that?

The first term in the 1st set of parentheses multiplies by each of the terms in the 2nd set of parentheses.

Then the second term in the 1st set of parentheses multiplies by each of the terms in the 2nd set.

To say that in words for this specific example:

x multiplies by x, and then multiplies by 3.

-2 multiplies by x and then by 3.

Be careful with signs!

So here's how it ends up looking:

`x^(2) + 3x -2x -6 = 0`

Then you have to group like terms:

`x^(2) + (3x - 2x) - 6 = 0`

Combine the things in parentheses:

`x^(2) + x - 6 = 0`