Question

1) x-1+5
`√(x-1\\)`+3=0
4)
`x^(4)` -64=0

Answer 1

See explanation below

Explanation:

Find the value of x in each of the following

1) x-1+5√x-1+3=0

5√x-1 = -x -2

Square both sides

25(x-1) = (-x-2)^2

25(x-1) = x^2+4x + 4

25x-25 = x^2+4x + 4

x^2 +4x + 4 - 25x + 25 = 0

x^2 - 21x + 29 = 0

x = 21±√21²-4(29)/2

x = 21±√441-116/2

x = 21±√325/2

x = 21±18.03/2

x = 21+18.03/2 and 21-18.03/2

x = 19.515 and 1.485

4) x^4-64=0

x^4 = 64

`x = \sqrt[4]{64}`

x = 2.83