Answer:
To find the numbers that are a distance of 3 units from 12 on a number line ranging from -5 to 17, we can use the concept of absolute value.
The absolute value of a number represents its distance from zero on a number line. To find the numbers that are a distance of 3 units from 12, we can calculate the absolute value of the difference between each number and 12, and check if it equals 3.
Let's go through each option and determine if it satisfies the condition:
A. 3: The absolute value of the difference between 3 and 12 is |3 - 12| = |-9| = 9, which is not equal to 3. So, option A is not correct.
B. 15: The absolute value of the difference between 15 and 12 is |15 - 12| = |3| = 3, which is equal to 3. So, option B is correct.
C. 9: The absolute value of the difference between 9 and 12 is |9 - 12| = |-3| = 3, which is equal to 3. So, option C is correct.
D. 0: The absolute value of the difference between 0 and 12 is |0 - 12| = |-12| = 12, which is not equal to 3. So, option D is not correct.
E. -9: The absolute value of the difference between -9 and 12 is |-9 - 12| = |-21| = 21, which is not equal to 3. So, option E is not correct.
F. negative 9: This is the same as option E, which is not correct.
G. -15: The absolute value of the difference between -15 and 12 is |-15 - 12| = |-27| = 27, which is not equal to 3. So, option G is not correct.
Therefore, the correct options are B. 15 and C. 9, as they are the numbers that are a distance of 3 units from 12 on the given number line.
Explanation:
<3