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Find the value of sin θ if sec θ = 7/2 and tan θ > 0. a) sin θ = 2/7 b) sin θ = 1/7 c) sin θ = 7/2 d) sin θ = 7/√53

User Youzef
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1 Answer

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Answer:

To find the value of sin θ given that sec θ = 7/2 and tan θ > 0, we can use the following trigonometric identities:

1. sec θ = 1/cos θ

2. tan θ = sin θ / cos θ

First, let's find the value of cos θ using the information provided:

sec θ = 7/2

Since sec θ = 1/cos θ, we can write:

1/cos θ = 7/2

Now, cross-multiply:

2 = 7cos θ

Now, solve for cos θ:

cos θ = 2/7

Next, we can use the fact that tan θ > 0 to determine the sign of sin θ. In the context of the unit circle, this means that θ must be in the first quadrant or the third quadrant, where sin θ is positive.

Now, we have cos θ = 2/7, and we can use the Pythagorean identity for sine:

sin θ = √(1 - cos² θ)

sin θ = √(1 - (2/7)²)

sin θ = √(1 - 4/49)

sin θ = √(45/49)

sin θ = √(9/9) * √(5/7)

sin θ = (3/3) * (√5/√7)

sin θ = (√5/√7)

Now, rationalize the denominator:

sin θ = (√5/√7) * (√7/√7)

sin θ = (√5√7)/(√7√7)

sin θ = (√35)/7

So, the value of sin θ is sin θ = (√35)/7, which is approximately equal to 0.748.

Therefore, the correct answer is not listed among the provided options.

Explanation:

User Nickey
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