234k views
5 votes
Someone tell me the answer pls

Someone tell me the answer pls-example-1

1 Answer

2 votes

Answer:

To find the zeros of the quadratic equation x² - 4x + 5, we can use the quadratic formula. The quadratic formula states that for any quadratic equation of the form ax² + bx + c = 0, the zeros can be found using the formula:

x = (-b ± √(b² - 4ac))/(2a)

In this case, the coefficients of the quadratic equation are a = 1, b = -4, and c = 5. Plugging these values into the quadratic formula, we get:

x = (-(-4) ± √((-4)² - 4(1)(5)))/(2(1))

x = (4 ± √(16 - 20))/2

x = (4 ± √(-4))/2

Here, we have a square root of a negative number (√(-4)), which means that the zeros will be complex numbers. Let's simplify the equation further:

x = (4 ± 2i)/2

Now, we can simplify the expression by dividing both the numerator and denominator by 2:

x = 2 ± i

So, the zeros of the quadratic equation x² - 4x + 5 are:

x = 2 + i

x = 2 - i

These are the complex zeros of the equation.

Explanation:

User HMcG
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories