Question

Matter is in a liquid state when its temperature is between its melting point and its boiling point. Suppose that some substance has a melting point of -44.29°C and a boiling point of 365.31 °C. What is the range of temperatures in degrees Fahrenheit for which this substance is not in a liquid state? (Hint: C = - 9 (F-32)) Express the range as an inequality. a)-112.12°F < F < 283.57°F b)-107.62°F < F < 279.27°F c)-116.12°F < F < 287.57°F d)-102.62°F < F < 284.27°F

Answer 1

To find the range of temperatures in degrees Fahrenheit for which the substance is not in a liquid state, we convert the melting and boiling points given in Celsius to Fahrenheit using the given formula and express the temperatures as an inequality.

Step-by-step explanation:

This question is about determining the temperature range in degrees Fahrenheit at which a substance is not in a liquid state. The substance has a melting point of -44.29°C and a boiling point of 365.31 °C. We will use the formula C = 9/5 (F-32) to convert these temperatures to Fahrenheit.

To convert the melting point to Fahrenheit, we have -44.29 = 9/5 (F-32), which gives us F = -47.322°F. Similarly, for the boiling point, we have 365.31 = 9/5 (F-32), which gives F = 689.558°F. Therefore, below -47.322°F and above 689.558°F, the substance is not in a liquid state. You can express these temperatures as an inequality F < -47.322°F or F > 689.558°F.

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