Question

Given a line passes through point (5,8) and the origin, find the equation of the line.
y=

Answer 1

y = 8/5x

Explanation:

I'm assuming that they're asking for the equation in point-slope form.

The formula is y=mx+b where:

m = slope

b = y intercept

However, the y intercept is just (0,0) so b = 0

To find the slope we already have 2 given points: (0,0) and (5,8)

To find slope you do rise/run and you get 8/5

Substitute the slope & y intercept in the formula:

y = 8/5x

Let me know if I'm wrong!!

Answer 2

y=8/5x

Explanation:

Hi there!

We need to find the equation of the line that passes through (5,8) and the origin (the point (0,0)).

There are 3 ways to write the equation of the line, although the most common way is slope-intercept form, or y=mx+b where m is the slope and b is the y intercept

first, let's find m (slope)

The formula for the slope calculated from two points is
`(y_(2)-y_(1))/(x_(2)-x_(1))`, where (
`x_(1)`,
`y_(1)`) and (
`x_(2)`,
`y_(2)`) are points

we have two points, but let's label their values to avoid any confusion

`x_(1)`=5

`y_(1)`=8

`x_(2)`=0

`y_(2)`=0

now substitute into the formula

m=
`(y_(2)-y_(1))/(x_(2)-x_(1))`

m=
`(0-8)/(0-5)`

multiply

m=
`(-8)/(-5)`

divide

m=8/5

The slope of the line is 8/5

here's the equation so far

y=8/5x+b

now we need to find b

as the point will pass through both (5,8) and (0,0) we can use either one of them to solve for b

let's take (0,0) as an example

substitute 0 as x and 0 as y

0=8/5(0)+b

multiply

0=0+b

add

0=b

substitute 0 as b into the equation

Therefore the equation of the line is:

y=8/5x (the 0 is not necessary)

Hope this helps! :)