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What are the coordinates of the point on the directed line segment from (-7,-10) to (1,-6) that partitions the segment into a ratio of 3 to 1

User Johnnieb
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1 Answer

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Answer: (-1, -7)

Explanation:

To find the coordinates of the point on the directed line segment from (-7, -10) to (1, -6) that partitions the segment into a ratio of 3 to 1, you can use the following formula:

\[P(x, y) = \left(\frac{{3x_2 + 1x_1}}{4}, \frac{{3y_2 + 1y_1}}{4}\right)\]

Where:

- (x, y) are the coordinates of the point we're trying to find.

- (x_1, y_1) are the coordinates of the starting point (-7, -10).

- (x_2, y_2) are the coordinates of the ending point (1, -6).

Now, plug in the values:

\[P(x, y) = \left(\frac{{3(1) + 1(-7)}}{4}, \frac{{3(-6) + 1(-10)}}{4}\right)\]

\[P(x, y) = \left(\frac{{3 - 7}}{4}, \frac{{-18 - 10}}{4}\right)\]

\[P(x, y) = \left(\frac{{-4}}{4}, \frac{{-28}}{4}\right)\]

\[P(x, y) = (-1, -7)\]

So, the coordinates of the point that partitions the segment into a ratio of 3 to 1 are (-1, -7).

User Nirmal Dhara
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