Question

For her birthday party Jasmine mixed together 5 L of Brand A fruit punch and 3 L of Brand B. Brand A contains 22% fruit juice and Brand B contains 14% fruit juice. What percent of the mixture is fruit juice?

Please show all workings :)

Answer 1

we can break this down to some simple steps to find out what percentage of the fruit punch mixture is real fruit juice.

Step 1: Calculate the amount of juice in Brand A fruit punch.
Brand A fruit punch has a volume of 5 L and it contains 22% fruit juice. Therefore, we can find the volume of juice in Brand A by taking 22% of 5 L. It comes out to be 1.1 L.

Step 2: Calculate the amount of juice in Brand B fruit punch.
Brand B has a volume of 3 L and it contains 14% fruit juice. Similar to step 1, we can find the quantity of juice in Brand B by taking 14% of 3 L. This gives us 0.42 L.

Step 3: Calculate the total volume of juice in the mixture.
Adding the quantities of juice in Brand A and Brand B together, we get the total amount of juice in the mixture. This comes out to be 1.1 L + 0.42 L = 1.52 L.

Step 4: Calculate the total volume of the fruit punch mixture.
The total volume of the fruit punch mixture is the sum of the volumes of Brand A and Brand B. Hence, total volume = 5 L + 3 L = 8 L.

Step 5: Calculate the fruit juice percentage in the mixture.
Now that we have the total volume of fruit juice and the total volume of the mixture, we can find the fruit juice percentage by dividing the volume of juice by the total volume and then multiplying the result by 100 to convert it into percentage. Therefore, juice percentage = (1.52 L / 8 L) * 100 = 19%.

So, 19% of Jasmine's fruit punch mixture is real fruit juice.