Final answer:
To find the perimeter of a triangle with specified vertices, calculate the distance between each pair of points using the formula for calculating distance in a coordinate plane. In this case, the distances were 3 units, 4 units, and 5 units, adding up to a perimeter of 12 units.
Step-by-step explanation:
The problem is to find the perimeter of a triangle with vertices at (-1,-1), (2,-1) and (2,3). To solve this, we need to find the distance between each pair of points (vertices), which will give us the sides of the triangle. The formula for calculating distance between two points (x1, y1) and (x2, y2) in a coordinate plane is √[(x2-x1)² + (y2-y1)²].
- Distance between (-1, -1) and (2,-1) is √[(2-(-1))² + ((-1)-(-1))²] = √[3² + 0] = 3 units.
- Distance between (2,-1) and (2,3) is √[(2-2)² + (3-(-1))²] = √[0 + 4²] = 4 units.
- Distance between (2,3) and (-1,-1) is √[(2-(-1))² + (3-(-1))²] = √[3² + 4²] = 5 units.
Adding these distances together gives us the perimeter of the triangle: 3 + 4 + 5 = 12 units.
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