Answer:
The correct answer is "-1.5 cm".
Step-by-step explanation:
The given values are:
Object is placed,
u = 2.5 cm
Focal length,
f = 1.5 cm
On applying the lens formula, we get
⇒

or,
⇒

On substituting the given values, we get
⇒

⇒

⇒

⇒

As we know,
Magnification,

On substituting the values, we get
⇒

⇒
