36.4k views
5 votes
Find the sum of the first 100 positive integers exactly divisible by 7

User ACRL
by
8.5k points

1 Answer

5 votes

Answer:

Hi,

Explanation:

Number of multiple of 7:100

First+ last =7+700=707

sum= 100*707/2=35350

or


\displaystyle 7+14+21+...+700=\sum_(i=1)^(100) 7*i\\=7*\sum_(i=1)^(100) i\\\\\\=7*(100*101)/(2)\\\\=35350\\

User Uzoamaka
by
6.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories