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A man walks 12 km East and 7 km north. What distance did he walk? What is his displacement:

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Final answer:

The man walked a total distance of 19 km (12 km East and 7 km North). His displacement, computed using Pythagoras' theorem, is approximately 13.89 km.

Step-by-step explanation:

The man in question walked a total distance of 19 kilometers, given by summing up his eastward journey of 12 km and his northward journey of 7 km. However, the displacement, which is the shortest distance between his starting point and final point, can be calculated using Pythagoras' theorem (as this forms a right-angled triangle). So, displacement = (√((12 km)² + (7 km)²)) = √(144 + 49) = √193 km ≈ 13.89 km.

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