Answer:
(x - 6)(2x + 3)
Explanation:
This is quadratic.
Quadratic form:
a^2 + bx + c
First bring down the first and last term and enclose them in parenthesis then add them.
Next, find two numbers that multiply to equal AC and that add to B.
2x^2 - 9x - 18
First find what AC multiplies to:
2(-18) = -36
What two numbers multiply to -36x^2 and add to -9x.
-12x and 3x, (-12 · 3 = -36 and -12 + 3 = -9).
By finding these two numbers, we split the middle term.
Now group them together as you add one of these two numbers to one parenthesis and the other number to the other parenthesis, (2x^2) and (-18).
(2x^2 - 12x) + (3x - 18)
Find a common factor:
2x(x - 6) + 3(x - 6)
Now add the terms that are being multiplied with the different parenthesis and multiply them with one of the expressions in the parenthesis.
(rewriting in factored form)
(2x + 3)(x- 6)
= (x - 6)(2x + 3)