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Describe the motion of a particle given by the function t^2−3t, where t is greater than zero.

User Titogeo
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Final answer:

The motion of the particle given by the function t^2 - 3t involves position, velocity, and acceleration. The position of the particle can be determined by substituting the value of t into the function. The velocity and acceleration can be found by taking the derivatives of the position function.

Step-by-step explanation:

The motion of the particle given by the function t^2 - 3t, where t is greater than zero, can be described using the concepts of position, velocity, and acceleration. To determine the particle's position at any given time, we can substitute the value of t into the function. For example, if we substitute t = 2, we get (2^2) - (3*2) = 4 - 6 = -2. This means that the particle is at a position of -2 units at t = 2.

To find the velocity of the particle, we can calculate the derivative of the position function with respect to time. In this case, the derivative of the function t^2 - 3t is 2t - 3. Similarly, to find the acceleration, we can calculate the derivative of the velocity function. In this case, the derivative of 2t - 3 is 2.

Therefore, the motion of the particle can be described as follows: at any given time t, the particle's position is given by the function t^2 - 3t. The velocity of the particle is 2t - 3, and the acceleration is 2.

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