Question

A baseball is thrown horizontally from a cliff at 30 m/s and lands 7 seconds after the baseball was thrown. Calculate the horizontal AND vertical distance.

Answer 1

The horizontal and vertical distances are x = 210 m and y = -240.35 m, respectively.

Step-by-step explanation:

Using the equation of the displacement in the x-direction, we have:

(let's recall we have a constant velocity in this direction)

`x=v_(ix)t`

Where:

• v(ix) is the initil velocity in the x direction (v(ix) = 30 m/s)
• t is the time (t = 7 s)

`x=30(7)`

`x=210\: m`

Now, we need to use the equation of the displacement in the y-direction to find the vertical distance. Here we have an acceleration (g)

`y=v_(iy)t-(1)/(2)gt^2`

Where:

• v(iy) is the initial velocity at the y-direction. In this case, it will be 0
• t is the time
• g is the acceleration of gravity (g=9.81 m/s²)

Then, the vertical position at 7 s is:

`y=-(1)/(2)(9.81)(7)^2`

`y=-240.35\: m`

Therefore, the horizontal and vertical distances are x = 210 m and y = -240.35 m, respectively. The minus sign means the negative value in the y-direction.

I hope it helps you!