Question

A plane is flying to Minnesota with a velocity of 372.32 km/h, N. The plane

encounters a crosswind with a velocity of 76.66 km/h, W. What is the magnitude of
the resultant velocity of the plane? (Answer in km/h)

Answer 1

To find the magnitude of the resultant velocity of the plane, we can use vector addition.

Given:
Velocity of the plane (in the north direction) = 372.32 km/h, N
Velocity of the crosswind (in the west direction) = 76.66 km/h, W

Since the velocities are in different directions, we can consider them as vectors. To find the resultant velocity, we can use the Pythagorean theorem.

The magnitude of the resultant velocity can be calculated using the formula:

Resultant velocity = √(velocity of the plane)^2 + (velocity of the crosswind)^2

Resultant velocity = √(372.32^2 + 76.66^2)

Resultant velocity ≈ √(138652.7424 + 5879.3156)

Resultant velocity ≈ √(144532.058)

Resultant velocity ≈ 380.2 km/h

Therefore, the magnitude of the resultant velocity of the plane is approximately 380.2 km/h.