Question

At the beginning of each year, she tracks the wild turkey and white-tail deer population in the game reserve where she works. At the first year Sheila counted 12 wild turkeys, and their number increases by approximately 40% each year. At the first year Sheila counted 181818 white-tail deer, and their number increases by 10 additional deer per year. What is the first year in which Sheila counts more turkeys than deer?

Answer 1

Sheila starts off with 12 turkeys and 181818 deer. The turkeys' count then grows by 40% annually and the deer count increases by 10 each year. To find out when she has more turkeys than deer, we have to solve the equation of 12 * 1.4^n > 181818 + 10n, which entails using advanced mathematical methods.

Step-by-step explanation:

Sheila counts 12 wild turkeys initially and this number increases annually by roughly 40%. Their count after n years can be represented by the exponential function 12 * 1.4^n. She counts 181818 white tail deer in the first year and this number increases by 10 each year. The count of deer could be represented by the linear function 181818 + 10n. Hence, Sheila will count more turkeys than deer when 12 * 1.4^n > 181818 + 10n. Since this involves an exponential equation, trial and error or a higher-level mathematical method such as logarithms may be necessary to solve for 'n'.

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