Question

Factor completely 16a^2+48a+36

Answer 1

the answer to you problem is

4(2a+3)^2

Answer 2

`4(2a+3)^2`

Explanation:

`16a^(2)+48a+36`

The whole function can reduced by a factor of 4, so divide everything by 4

`4(4a^2+12a+9)`

Then factor the inside

`4(4a^2+6a+6a+9)`

`4[2a(2a+3)+3(2a+3)]`

`4(2a+3)(2a+3)`

Since (2a+3) occurs twice you can rewrite it squared

`4(2a+3)^2`