Question

Which is the equation of a trend line that passes through the points (3, 95) and (11, 12) ? Round values to the nearest ten-thousandths.

answer choices
y=−10.375x+126.125

y=−0.096x+13.056

y=10.375x+63.875

y=0.096x+10.944

Answer 1

To find the equation of a trend line, we can use the slope-intercept form: y = mx + b.

Using the given points (3, 95) and (11, 12), we can calculate the slope (m) as (12 - 95) / (11 - 3) = -83 / 8 ≈ -10.375.

Next, we can substitute one of the points into the equation to solve for the y-intercept (b). Using (3, 95), we have 95 = -10.375 * 3 + b. Solving for b gives us b ≈ 126.125.

Therefore, the equation of the trend line is y = -10.375x + 126.125.

So, the correct answer is A. y = -10.375x + 126.125.

hope this helped :)